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qaws [65]
3 years ago
8

Can yall actually help I need jus 3 and 6

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

3.) (x,y)⇒(x+9,y-5)

6.) T'= (-4,5) U'= (1,-7) V'= (2,4) W'= ( 7,2) X'=( 5,-10) Y'=( 0,2) Z'= ( 8,-3)

Step-by-step explanation:

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balu736 [363]
<span>The resent value, also called "discounted value," is the current worth of the camera. So, we know that the discounted value is $105.00.
The first price of the camera was $120.00.
This means that the price is decreased. In order to calculate the discount rate we should find out how many percent the camera was discounted. 105 from 120 is: 105/120*100=87.5
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3 years ago
Angela had $22.70 to spend on groceries. After buying 8 pineapples, she had $3.50 left. If each pineapple was the same price, wh
sesenic [268]

Answer:

$2.40

Step-by-step explanation:

First, you would do 22.70 minus 3.50, to get 19.20.

Then, you would divide 19.20 by 8, to get 2.4.

So, if each pineapple was the same price, each pineapple would be $2.40.

3 0
2 years ago
Point J has coordinates (–3, 4) in the coordinate plane. Point K has coordinates (3, 4). Both points will be reflected across th
kumpel [21]

The location of the image of points <em>J </em>and <em>K </em>following a reflection across the x-axis are;

  • J'(-3, -4), and K'(3, -4)

<h3>Which method can be used to find the image of a point following a reflection?</h3>

Coordinates of point are;

J(-3, 4), K(3, 4)

The given transformation is; A reflection across the x-axis

The representation of a reflection across the x-axis is presented as follows;

  • (x, y) → (x, -y)

The image of <em>J </em>and <em>K </em>following a transformation across the x-axis are therefore;

  • J(-3, 4) → J'(-3, -4)

  • K(3, 4) → K'(3, -4)

Learn more about reflection transformation on the coordinate plane here:

brainly.com/question/8242111

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8 0
2 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

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2 years ago
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Bobby because 2/3 is the largest number when divided
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3 years ago
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