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ehidna [41]
3 years ago
13

Solve for x: x - 35 = 45 A. 10 B. 15 C. 35 D. 80

Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:

X = 80

Step-by-step explanation:

Add 35 To Both Sides

X - 35 + 35 = 45 + 35

Simplify

X = 80

Best Of Luck,

- I.A. -

dezoksy [38]3 years ago
6 0

The answer is D. 80.

A and B are incorrect because they're less than 35, meaning they'll give you a  negative number, and the answer we're trying to get is positive.

C is incorrect because it's the same number as the one subtracting x, so you'd only get 0.

That leaves D, and if you do the math, 80 - 35 is 45.

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artcher [175]
The answer for your problem is x = 26
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Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

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3 0
3 years ago
The parents organization bought 1,000 bumper stickers at $1.25 each to sell at football games.They want to make at least $750 pr
yuradex [85]
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5 0
3 years ago
I need help understanding how to solve this problem.
LUCKY_DIMON [66]

Answer:

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Explanation:

It is indicated to <em>find the coordinates</em> of the <em>point T (5/13, 12/13) </em>at a distance <em>π + x.</em>

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Then, the distance π+ x means that the <em>point T</em> is rotated 180º.

The rule for the rotation of a point 180º around the origin is:

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Applying that rule to the point T:

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