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2 years ago

Solve for x: x - 35 = 45 A. 10 B. 15 C. 35 D. 80

Mathematics

2 answers:

Leya [2.2K]2 years ago

7 0

Answer:

X = 80

Step-by-step explanation:

Add 35 To Both Sides

X - 35 + 35 = 45 + 35

Simplify

X = 80

Best Of Luck,

- I.A. -

dezoksy [38]2 years ago

6 0

The answer is D. 80.

A and B are incorrect because they're less than 35, meaning they'll give you a negative number, and the answer we're trying to get is positive.

C is incorrect because it's the same number as the one subtracting x, so you'd only get 0.

That leaves D, and if you do the math, 80 - 35 is 45.

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Find the measure of ZDCF. C F mDF = 49 G E MEG = 127 Find the measure of angle DCF

AleksandrR [38]

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

Arc DF = 49

Solution

<DCF = 1/2(127 - 49)

<DCF = 1/2(78)

<DCF = 39

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2 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

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$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

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$m^{-1}=\dfrac{1}{m}$

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$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

2 years ago

2 a square root of 2 b square root 3 parentheses for a square root 2 + 380 square root 2 - 80 parentheses equal

velikii [3]

2√2

= 2√2

√3(√2+380√2-80)

= -80√3+381√6

I hope that's help and sorry for the late answer !

5 0

3 years ago