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swat32
3 years ago
13

What is the arc length when θ = 3 pi over 5 and the radius is 7 cm? (5 points)

Mathematics
1 answer:
erastova [34]3 years ago
4 0
The correct answer is 21π/5

Explanation:
The arc length of a circle is given as = radius × angle subtended by the arc at centre.
Here, r = 7 cm.
θ = 3π/5
Therefore, arc length, l = rθ = 7×3π/5 = 21π/5
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nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
3 years ago
3 15/16 divided by 2 5/8Ask your question here
Alexeev081 [22]
\frac{3 \frac{15}{16}  }{2 \frac{5}{8}}  \\  \\  \frac{ \frac{63}{16} }{ \frac{21}{8} }  \\  \\ \frac{63}{16}*\frac{8}{21} \\  \\  \frac{63*8}{16*21}  \\  \\  \frac{504}{336}  \\  \\ 1 \frac{168}{336}  \\  \\ 1 \frac{168:168}{336:336} \\  \\ 1 \frac{1}{2}
3 0
3 years ago
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