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2 years ago

What is the area of the trapezoid

Mathematics

2 answers:

Ronch [10]2 years ago

8 0

Answer: 108

Step-by-step explanation: the formula, 10+7(2)/2 x 9 = 108

Montano1993 [528]2 years ago

4 0

Answer:

153

Step-by-step explanation:

Triange area = 1/2 b*h

= 1/2 (7)*(9)

=31.5 (for 1 triangle)

2(31.5) = 63 (for 2 triangles, left and right)

Rectangle area = b *h

= 10*9

=90

Total = 2 triangles + rectangle

63+90 = 153

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2 years ago

Reduce the fraction 512/128 into the simplest form.

frez [133]

Answer:

Therefore, 512/128 simplified to lowest terms is 4/1.

Step-by-step explanation:

Reduce 512/128 to lowest terms

The simplest form of

512

128

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 512 and 128 is 128

Divide both the numerator and denominator by the GCD

512 ÷ 128

128 ÷ 128

Reduced fraction:

Therefore, 512/128 simplified to lowest terms is 4/1.

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2 years ago

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3 years ago

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The answer to the question

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3 years ago

Read 2 more answers

A circle is centered at the point (5, -4) and passes through the point (-3, 2).

zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

$\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10$

The standard form of equation of circle is:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where h and k are the coordinates of the center. So putting in the value:

$(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100$

8 0

3 years ago