Answer:
Circle A's attributes were used to be organized because both shapes have a <u>right angle</u>. Circle B's attributes were used to be organized because both shapes have <u>2 sets of parallel lines</u> that are across from each other. The middle was organized because both shapes have <u>2 sets of parallel lines</u> and <u>4 right angles</u>.
Step-by-step explanation:
Let me know if this helps!
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Cross multiply and solve for x:</u>
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer: 14s - 7s/2 = 84
Step-by-step explanation:
Given that s is the length of the unknown side:
Area of the shaded region = 84
Area of rectangle - Area of triangle = 84
Area of rectangle = L * W
= 14 * s
= 14s
Area of triangle = ¹/₂ * base * height
= ¹/₂ * 14 * s/2
= 7s/2
Area of shaded region:
14s - 7s/2 = 84
Solving for s:
14s - 7s/2 = 84
28s - 7s = 168
21s = 168
s = 168/21
s = 8 inches
