As a = 0 , there is no sign . Its only 0. Thus the answer is (c)
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
y = -x + 5
Step-by-step explanation:
X, Y, and B is given using fomula y = m(x) + b
Subsitute those variables.
0 = -(5) + b
Solve for m.
0 = -5 + b
+5 +5
b = 5.
Then plug in the b and take out the x and y.
y = -x + 5