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3 years ago

7

I need help I have this problem and I think it either has to be simplified or turned into a fraction but I’m really sure it’s si

mplified anyway the equation is 5x+5x=10x please help

1 answer:

Olenka [21]3 years ago

6 0

What are you specifially looking for? simplified it would be 10 and as a fraction 10 over 1

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Determine the best method to solve the system of equations. Then solve the system.

maxonik [38]

Answer:

x=1 y = -1/2

(1,-1/2)

Step-by-step explanation:

7x-2y=8

5x+2y=4

I would use elimination since we have 2y in one equation and -2y in the other

7x-2y=8

5x+2y=4

--------------------

12x = 12

Divide each side by 12

12x/12 = 12/12

x =1

The substitute back into equation 2

5(1) +2y = 4

5 +2y = 4

Subtract 5

5-5+2y = 4-5

2y = -1

Divide by 2

2y/2 = -1/2

y = -1/2

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3 years ago

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If there is a class of 30 students and 6 of them are off, what fraction of students are there and what percentage of students ar

elena-s [515]

As fraction it would be 6/30 reduced 1/5 and as percentage 20% so 20% of the students were off.<span />

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3 years ago

A cable repair person has 7.9 meters of wire. Suppose each meter of the wire weighs 3.2 ounces. Find the weight of the wire.

Maslowich

3.2 x 7.9 = 25.28
Hope this helps:D

8 0

3 years ago

I need help please. Only answer if you know

Wewaii [24]

Answer:

57

Step-by-step explanation:

first do what is in the brackets then the parentheses, then multiply the 3

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3 years ago

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If arc SQ = 84° and ∠RPS = 26°, what is the measure of arc RS? need answer asap thank you

Lera25 [3.4K]

Answer:

$arc\ RS=136\°$

Step-by-step explanation:

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m∠RPS= $26\°$ ------> external angle

so

m∠RPS= $\frac{1}{2}(arc\ RS-arc\ SQ)$

we have

m∠RPS= $26\°$

$arc\ SQ=84\°$

substitute the values

$26\°=\frac{1}{2}(arc\ RS-84\°)$

Solve for arc RS

$52\°=(arc\ RS-84\°)$

$arc\ RS=52\°+84\°=136\°$

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3 years ago

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