The perimeter of the triangle shown are equal. Find the side lengths of each triangle.
2 answers:
Good morning ☕️
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Step-by-step explanation:
Let p1 be the perimeter of triangle ABC
p2 be the perimeter of triangle PQR
p1=(2x+4)+(2x+3)+(2x) = 6x+7
p2=(2x)+(2x)+(3x+1) = 7x+1
p1=p2 ⇔ 6x+7=7x+1 ⇔ 7x-6x=7-1 ⇔x=6
Then :
AC=2(6)=12
AB=2(6)+4=16
BC=2(6)+3=15
PQ=12
QR=12
PR=3(6)+1=19.
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:)
Answer:
12,16,15 and 12,12,19
Step-by-step explanation:
Hello, I think I can help you with this.
the perimeter of a triangle is the sum of its three sides
Perimeter = side1+side2+side3
Step 1
Perimeter1=(2x+4)+(2x+3)+2x
P1=2x+4+2x+3+2x
P1=6x+7
Step 2
Perimeter2=2x+2x+(3x+1)
P2=2x+2x+3x+1
P2=7x+1
Step 3
find x,
P1=P2
6x+7=7x+1
7-1=7x-6x
6=x
x=6
Step 4
replace the value of x to find each side length
triangle1(left)
2x=2(6)=12
<u>2x=12</u>
2x+4=12+4=16
<u>2x+4=16</u>
2x+3=12+3=15
<u>2x+3=15</u>
triangle2(right)
2x=2(6)=12
<u>2x=12</u>
3x+1=3(6)+1=18+1=19
3x+1=19.
Have a great day
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