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Anon25 [30]
2 years ago
7

PLEASE HELP

Mathematics
1 answer:
tekilochka [14]2 years ago
5 0

Question 19

<h3>Answer: No, it is not in quadrant 3.</h3>

Explanation:

In order to be in quadrant 3, we need two things

  • x must be negative
  • y must be negative

An example point in the third quadrant is (-9, -12).

Both (x,y) coordinates must be negative to be located in quadrant 3. This is the southwest quadrant on the xy grid. We're told that x = 0 which means we are not in quadrant 3. Points on the x or y axis are not part of any quadrant. They are on the boundaries between quadrants (think of it like a fence or a wall).

============================================================

Question 20

<h3>Answer: No, it is not in quadrant 2</h3>

Explanation:

We use a very similar idea as the previous question. Since y = 0, this point is on a boundary and not in any quadrant. To be in the second quadrant, we need these two conditions to be true:

  • x must be negative
  • y must be positive

For example, the point (-5, 7) is in quadrant 2. This quadrant is in the northwest on the xy grid.

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Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

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Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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