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alexgriva [62]
3 years ago
11

Add: 6(x + 7) + (x + 3

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0
The answer is
6X+42+x+3
7x+ 45
Aneli [31]3 years ago
7 0

Answer:

x=45/7

Step-by-step explanation:

=6x+42+x+3

6x+x+42+3

7x+45

x=45/7

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What is the base 8 representation of the number 11100111(2)
kondor19780726 [428]

Remark

You could convert base two to base 10 and then convert base 10 to base 8. That's the long way. The procedure below is the short way.

Step One

Write the base 2 number in groups of 3 starting from the right and going left

11 100 111

Step Two

Convert the base 2 numbers in groups of 3 to base 8. The largest result will be a 7

11 = 2*1 + 1 = 2 + 1 = 3

100 = 1*2^2 = 4

111 = 1*2^2 + 1*2 + 1 = 7

Step Three

Read the answer going down.

347 is the answer

Answer

347(8) = C


5 0
3 years ago
55" TV: $669 with a 23% markup
Flauer [41]

Answer:

what is the question?

Step-by-step explanation:

6 0
2 years ago
A recipe requires 1/5 cup of milk for each 1/4 cup of water. How many cups of water are needed for each cup of milk?
Lelechka [254]

Answer:

1 1/4

Step-by-step explanation:

trust my guy just keep adding until you get 1 cup of milk

4 0
3 years ago
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
3 years ago
arius flipped a coin 500 times and it landed heads up 300 times. What is the relative frequency of the coin landing heads up bas
guajiro [1.7K]

Answer:

3/5

Step-by-step explanation:

500 time number of coin flipped =500

pro.of relative freq.of head =300

relative frequency =300/500

=3/5

3 0
3 years ago
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