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crimeas [40]
3 years ago
14

PLEASE ANSWER RIGHT AWAY

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

D) 43.1

Step-by-step explanation:

What we want to do here is find the total volume of the box in cubic inches, then divide it by the number of apples inside. This will tell us how big one apple is in cubic inches.

Box One:

20×13×12 = 3120

3120÷72 apples = 43.3 inches³

Box Two:

12×12×12 = 1728

1728 ÷ 40 = 43.2 inches³

Box Three:

20×10×6 = 1200

1200÷28 = 42.8 inches³

Take those three numbers and find their mean. Add them up and divide by three. You will get 43.1 inches ³.

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Step-by-step explanation:

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Britney has a gift box in the shape of a cube. Each side of the box measures 15 centimeters. What is the volume of the gift box?
zavuch27 [327]
To get the volume, u have to multiply length*width*height. And cubes have equal side lengths, so 15*15*15= 3,375.

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timurjin [86]
B A C

The longest angle is opposite to the longest side in a triangle. The same goes for the shortest and middle angles.

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3 years ago
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Vlad1618 [11]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Find cos θ given that cos 2θ = 5/6 and 0 ≤ θ < π/2. Give an exact answer
trasher [3.6K]
\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
1-2sin^2(\theta)\\
\boxed{2cos^2(\theta)-1}
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\


\bf cos(2\theta)=\cfrac{5}{6}\implies 2cos^2(\theta)-1=\cfrac{5}{6}\implies 2cos^2(\theta)=\cfrac{5}{6}+1
\\\\\\
2cos^2(\theta)=\cfrac{11}{6}\implies cos^2(\theta)=\cfrac{11}{12}\implies cos(\theta)=\pm\sqrt{\cfrac{11}{12}}


now, bear in mind, the square root gives us +/- versions, so, which is it? well, we know the angle is in the range of "<span>0 ≤ θ < π/2", that simply means the 1st quadrant, so, we'll use the positive one then

</span>\bf cos(\theta)=\cfrac{\sqrt{11}}{\sqrt{12}}\implies cos(\theta)=\cfrac{\sqrt{11}}{2\sqrt{3}}&#10;\\\\\\&#10;\textit{now, let's rationalize the denominator}&#10;\\\\\\&#10;\cfrac{\sqrt{11}}{2\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{11}\cdot \sqrt{3}}{2\sqrt{3^2}}\implies \cfrac{\sqrt{11\cdot 33}}{2\cdot 3}\implies \boxed{\cfrac{\sqrt{33}}{6}}<span>
</span>
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4 years ago
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