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3 years ago

Determine the value of b so that the equation has no solution.

Mathematics

1 answer:

pav-90 [236]3 years ago

8 0

Answer:

c. b < 0

Step-by-step explanation:

l (x - 3)^2 - 4 l = l x^2 -6x + 9 - 4l

l x^2 - 6x + 5 l = b

If b < 0, the equation cannot be factored, there will not be real solution.

Therefore, answer is c. b< 0

Hope this will helpful.

Thank you.

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PLASE ANSWER THIS QUESTION I GIVE YOU 18 POINTS

sukhopar [10]

Answer:

(a) 144

(b) 117

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

(a)

$72 = 2^3 \times 3^2$

$144 = 2^4 \times 3^2$

$LCM = 2^4 \times 3^2 = 8 \times 9 = 144$

(b)

$39 = 3 \times 13$

$117 = 3^2 \times 13$

$LCM = 3^2 \times 13 = 117$

(c)

$72 = 2^3 \times 3^2$

$90 = 2 \times 3^2 \times 5$

$LCM = 2^3 \times 3^2 \times 5 = 360$

(d)

$84 = 2^2 \times 3 \times 7$

$147 = 3 \times 7^2$

$LCM = 2^2 \times 3 \times 7^2 = 588$

(e)

$152 = 2^3 \times 19$

$288 = 2^5 \times 3^2$

$LCM = 2^5 \times 3^2 \times 19 = 5472$

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2 years ago

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Step-by-step explanation:

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What is the area of a rectangle with vertices at (0, −4) , (−1, −3) , (2, 0) , and (3, −1) ? Enter your answer in the box

Bad White [126]

We are given vertices of a rectangle (0, −4) , (−1, −3) , (2, 0) , and (3, −1).

Length is the distance between (0, −4) and (−1, −3) points.

Width is distance between (−1, −3) and (2, 0) points.

<u>Computing length:</u>

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$