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irakobra [83]
3 years ago
7

Find the LCM of 52 and 39

Mathematics
2 answers:
qwelly [4]3 years ago
8 0
Lcm of 52 and 39 is 156
allochka39001 [22]3 years ago
5 0

The answer should be 156

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20 points!! Pls help
Studentka2010 [4]

Answer:

<h3>(-4, 1)</h3>

Step-by-step explanation:

-x-3=y, therefore x = -y-3

-3x - 8y = 4

Find the value of y

Substitute the x in -3x - 8y = 4 with -y-3

We get

-3·(-y-3) - 8y = 4

3y + 9 - 8y = 4

-5y = 4-9

-5y = -5

<h3>y = 1</h3>

_______________

Find the value of x

x = -y-3

x = -1-3

<h3>x = -4</h3>

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Answer (x, y) =

<h3>(-4, 1)</h3>

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Answer:

Step-by-step explanation:

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3 years ago
Please help asap 30 pts
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14-4y\geq38\qquad|\text{subtract 14 from both sides}\\\\-4y\geq24\qquad|\text{change the signs}\\\\4y\leq-24\qquad|\text{divide both sides by 4}\\\\y\leq-6\\\\Answer:\ \boxed{d.\ y\leq-6}

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Simplify the monomials
Zielflug [23.3K]

Answer:

(4a)^{-3}*^{-4}

x^m*x^n=x^{m+n}

(4a)^{-3}*a^{-4}

(-4)^{-3}\: a^{-3}*a^{-4}

4^{-3}\:a^{-3-4}

\cfrac{1}{4^3} \:a^{-7}

\boxed{\frac{1}{64a^{7}} }

~

(3xy)^2*(-4x^3y^2)^3

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\boxed{-576x^{11}y^8}

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(4a^{-1}b^5c^{-3})^3

(4)^3(a^{-1})^3(b^5)^3(c^{-3})^3

(4*4*4)\:a^{-1*3}\:b^{5*3}\:c^{-3*3}

64\:a^{-3}b^{15}c^{-9}

\boxed{\frac{64b^{15}}{a^3c^9}}

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2 years ago
1,900 joggers run at the city park every morning at 6 A.M. Of 190 asked, 35 of them enjoy running that early. Predict how many o
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