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irakobra [83]
3 years ago
7

Find the LCM of 52 and 39

Mathematics
2 answers:
qwelly [4]3 years ago
8 0
Lcm of 52 and 39 is 156
allochka39001 [22]3 years ago
5 0

The answer should be 156

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885 ÷ 4. Write the quotient and remainder
3241004551 [841]

Answer:

221 remainder 1

Step-by-step explanation:

885/4 is equal 221.25

This means that the quotient is 221, and when multiplying 221 by four gets us 884. 885 - 884 has a remainder of 1

8 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
What is the value of the expression?
nadya68 [22]
B use the app Photomath it helps you with this kinda questions
8 0
3 years ago
Combine the rational expressions into a single fraction and reduce it in the lowest terms.
Lostsunrise [7]

Answer:

13. -3                14. (x+1)(2x-7) / (x-6)(x+3)

Step-by-step explanation:

5 0
3 years ago
Find the value of y.
Phoenix [80]

\boxed{y=6\sqrt{3}}

<h2>Explanation:</h2>

For a better understanding of the problem I've built up two triangles from the given triangular shape. So these two triangles are similar. Therefore, we can solve this problem by using ratios and corresponding sides in this way:

\frac{x}{3}=\frac{12}{x} \\ \\ x^2=36 \\ \\ x=\sqrt{36} \\ \\ x=6

But our goal is to find y. Let's call w the height of the small triangle, then:

w=\sqrt{6^2-3^2}=3\sqrt{3}

Applying the concept of ratios again:

\frac{y}{w}=\frac{x}{3} \\ \\ y=w \left(\frac{x}{3}\right) \\ \\ y=3\sqrt{3}\left(\frac{6}{3}\right) \\ \\ \boxed{y=6\sqrt{3}}

<h2>Learn more:</h2>

Right triangle: brainly.com/question/10684799

#LearnWithBrainly

4 0
3 years ago
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