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laiz [17]
3 years ago
15

In how many ways can we pick three different numbers out of the group

Mathematics
1 answer:
ELEN [110]3 years ago
4 0

i will bite - this is not a complete ans but an approximation:

there are 100*99*98 ways to pick 3 different no. out of 100

if 2 of the no. picked are >10, then there is no way the third no. can be larger than the products of the other 2 nos.

there are 90*89*98 ways to pick 2 nos between 10 and 100 and a third no. between 1 and 100.

So an approximate ans = 100*99*98 - 90*89*98 = 185220 but the actual ans will be smaller than this.



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Answer correclty PLZZZ
ioda

Answer: option C is the correct answer

Step-by-step explanation:

The system of linear equations is

10x + 7y = 12 - - - - - - - 1

8x + 7y = 18 - - - - - - - 2

Since the coefficient of y is the same in equation 1 and equation 2, we will eliminate y by subtracting equation 2 from equation 1, it becomes

10x - 8x + 7y - 7y = 12 - 18

2x = -6

x = - 6/2 = - 3

Substituting x = - 3 into equation 1, it becomes

10×-3 + 7y = 12

-30 + 7y = 12

Let the constants be on the right hand side and the term containing y be on the left hand side. It becomes

7y = 12 + 30

7y = 42

y = 42/7

y = 6

C) (−3, 6)

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3 years ago
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