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GuDViN [60]
3 years ago
9

Determine the gradient of line AC​

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

This formula can also be written as \(y - {y}_{1} = m\left(x - {x}_{1}\right)\). The standard form of the straight line equation is \(y = mx + c\) where \(m\) is the gradient and \(c\) is the \(y\)-intercept.

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Which shape is similar to the original shape?<br> A) A <br> B) B <br> C) C <br> D) D
Anna35 [415]

Answer:

I think the answer is A.

Step-by-step explanation:

Original shape: 7 x 5 x 225 x 6 x 12 x 45 = 25,515,000

A: 9 x 5 x 225 x 6 x 35 x 12 = 25,515,000

B: 14 x 10 x 255 x 12 x 24 x 45 = 462,672,000

C: 9 x 7 x 225 x 8 x 15 x 45 = 76,545,000

D: 8 x 4 x 225 x 6 x 12 x 35 = 18,144,000

This is probably not the way you would solve it but this is how I did it. Basically I multiplied all the numbers in each shape together.

<em>(also i'm not quite sure if this is right >.< sorry!)</em>

8 0
3 years ago
A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?​
zzz [600]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf 240 \:  {inches}^{2} }}}}

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

\boxed{ \sf{perimeter = 2(l + w)}}

plug the values

⇒\sf{64 = 2(20 + w)}

Distribute 2 through the parentheses

⇒\sf{64 = 40 + 2w}

Swap the sides of the equation

⇒\sf{40 + 2w = 64}

Move 2w to right hand side and change it's sign

⇒\sf{2w = 64 - 40}

Subtract 40 from 64

⇒\sf{2w = 24}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{24}{2} }

Calculate

⇒\sf{w = 12 \: inches}

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

\boxed{ \sf{area \: of \: rectangle = length \:  \times  \: \: width}}

plug the values

⇒\sf{area \: of \: rectangle =20 \times  12 }

Multiply the numbers : 20 and 12

⇒\sf{area \: of \: rectangle = 240 \:  {inches}^{2} }

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0
3 years ago
In the triangle below, what is the length of the side opposite the 30 degree angle?
Vitek1552 [10]

Answer:

A. 3/2

Step-by-step explanation:

To find the lenght of the side opposing the 30° angle, you need to use trigonometry, since it's a right-angled triangle. You have your 30° angle and you have the side beside : therefore, you can use the sine :

sin(30) x 3 = ?

0,5 x 3 = ?

1,5 = ?

1,5 = 3/2

5 0
3 years ago
A cable company charges $70 per month for cable service to existing customers
Pachacha [2.7K]

Answer:

70x=y

70 per month=y, the cost

8 0
3 years ago
How do I do this help
tatuchka [14]
6÷40.5= $6.75 per hour
8÷54= $6.75 per hour
y= 6.75x
5 0
3 years ago
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