Is 21/23 bigger or smaller than 29/32

1 answer:

5 0

Think of a pie, if you cut it into 32 pieces the pieces would have to be small, and it you cut it into 23 pieces then the pieces would be bigger than the one cut I to 32 pieces. So 21/23 is bigger than 29/32

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I really need help on these two questions

Yuri [45]

$(4^\frac{1}{3} )^3$ =4
$(6^ \frac{1}{6} )^6$ =6
$(3^ \frac{1}{2} )^4$ =
multiply $\frac{1}{2}$ by 4
and then simplify
$3^{2}$

so it will be
4x6x9=216
your answer is d.216

3 0

3 years ago

For what value of x do the two ratios suggest a proportional relationship? 17 to 9; x to 99

Sidana [21]

Answer:

187

Step-by-step explanation:

9y=99

y=11

17y=x

x=187

3 0

3 years ago

Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using th

hodyreva [135]

I think the answer us A b doesn’t adds up

3 0

3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$