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Airida [17]
3 years ago
12

Probe that:

29%20%7D%20%20%5Calpha%20%20%3D%201" id="TexFormula1" title=" \sec \alpha \sqrt{1 - \sin( {}^{2} ) } \alpha = 1" alt=" \sec \alpha \sqrt{1 - \sin( {}^{2} ) } \alpha = 1" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

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There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Aca
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Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

P(A) = \frac{9}{92}

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

P(B) = \frac{10}{91}

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

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No

Step-by-step explanation:

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Step-by-step explanation:

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An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.
faltersainse [42]

Answer:

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

y=a(x-h)^2+k, (h,k) is the center

y=a(x-50)^2+25

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0=a(0-50)^2+25

subtract 25 from both sides

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divide both sides by 2500

a=-\frac{1}{100}

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

y=-\frac{1}{100}(40-50)^2+25

y=24

the height of the arch 10 feet from the center is 24 feet

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3 years ago
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