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UNO [17]
3 years ago
15

How can complex fractions be used to solve problems involving ratios

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
When you have ratios, and some unknowns, you can create complex fractions from them. Bring them to the same denominator, and solve for x.

Example - we have this proportion:
2-x
5-45
And we can change it into fraction:
\frac{2}{5}=\frac{x}{45}

\frac{2*9}{5*9}=\frac{x}{45}

\frac{18}{45}=\frac{x}{45}
18=x

In case of more complex fractions it may come in handy.
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Write an equation or system of equations to solve the problem below.
VashaNatasha [74]

Equations:

2x+105=-3x+130

<em>subtract</em><em> </em><em>2x</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em>

<em>105</em><em>=</em><em> </em><em>-5x</em><em>+</em><em>130</em>

<em>Subtract</em><em> </em><em>130</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>

<em>-5x</em><em>=</em><em> </em><em>-25</em>

<em>isolate</em><em> </em><em>the</em><em> </em><em>variable</em>

<em>x</em><em>=</em><em>5</em><em> </em>

<u>Plug</u><u> </u><u>back</u><u> </u><u>in</u>

<u>2</u><u>(</u><u>5</u><u>)</u><u>+</u><u>105</u><u>=</u><u> </u><u>-3</u><u>(</u><u>5</u><u>)</u><u>+</u><u>130</u>

<u>115</u><u>=</u><u> </u><u> </u><u>115</u>

5 0
3 years ago
Piano lessons cost $15. What expressions could be used to find the cost in dollars of 5 lessons
kirill115 [55]
Just write 15x5. Hope I helped
5 0
3 years ago
The function h is defined by h(x)=4+3x over 5+x<br><br> Find h(4z)
Jobisdone [24]

Answer:

h(4z)=4+12z / 5+4z

Step-by-step explanation:

The function h is defined by h(x)=4+3x over 5+x

This can be written as

h(x)=4+3x / 5+x

The value of the function at any time depends on the value of x. x is the independent variable. The variable,x can take any value at any time.

To find h(4z), it means that x is taking the value of 4z.

We will substitute 4z in the place of x in the function. This becomes

h(4z)=4+3×4z / 5+4z

h(4z)=4+12z / 5+4z

5 0
3 years ago
A biologist studied the populations of common guppies and Endler's guppies over a 6-year period. the biologist modeled the popul
Mice21 [21]
We can say that total number of guppies would simply be the sum of two polynomials.
To get our answers we need to add those two polynomials. We add polynomials by adding their like terms. Like terms are those that have the same exponent.
3.1x^2+6x+0.3+4.2x^2-5.2x+1=\\=(3.1x^2+4.2x^2)+(6x-5.2x)+(0.3+1)=\\&#10;=7.3x^2+0.8x+1.3
So the total amount of guppies would be modeled using this polynomial:
7.3x^2+0.8x+1.3
3 0
3 years ago
7( + 3) − 1 = 5( + 4) + 2
tankabanditka [31]

Answer:

False

Step-by-step explanation:

The left side 20 does not equal to the right side 22, which means that the given statement is false

3 0
3 years ago
Read 2 more answers
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