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UNO [17]
4 years ago
15

How can complex fractions be used to solve problems involving ratios

Mathematics
1 answer:
strojnjashka [21]4 years ago
5 0
When you have ratios, and some unknowns, you can create complex fractions from them. Bring them to the same denominator, and solve for x.

Example - we have this proportion:
2-x
5-45
And we can change it into fraction:
\frac{2}{5}=\frac{x}{45}

\frac{2*9}{5*9}=\frac{x}{45}

\frac{18}{45}=\frac{x}{45}
18=x

In case of more complex fractions it may come in handy.
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Answer:

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Step-by-step explanation:

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3 years ago
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Nutka1998 [239]

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3 0
3 years ago
Assume that the probability of having sickle cell anemia is 0.15 and the probability of being African-American is 0.45 in a give
irina1246 [14]

Answer:

the probability of having sickle cell anemia given that you are African-American is  P( B|A) =0.288

Step-by-step explanation:

Using Bayes's theorem

P( B|A) = P( A∩B)/P(A)

where P( B|A) = probability of the event B knowing that A happened , P( A∩B) = probability that A and B happen (joint probability of A and B) , P(A) = probability of event A

if B= probability of having sickle cell anemia and A= probability of being African-American

then

P( A∩B) = 0.13

P(A) = 0.45

then

P( B|A) = P( A∩B)/P(A)  = 0.13/0.45 = 0.288

P( B|A) =0.288

5 0
4 years ago
*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4
Georgia [21]

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

4 0
3 years ago
Read 2 more answers
What is 1199.28856995 to the nearest ten.
mart [117]

Answer:

1199.3

Step-by-step explanation:

1199.28856995

round 2 up to 3, because the next number is greater than 5 (which is 8)

8 0
3 years ago
Read 2 more answers
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