How can complex fractions be used to solve problems involving ratios

1 answer:

5 0

When you have ratios, and some unknowns, you can create complex fractions from them. Bring them to the same denominator, and solve for x.

Example - we have this proportion:
2-x
5-45
And we can change it into fraction:
\frac{2}{5}=\frac{x}{45}

\frac{2*9}{5*9}=\frac{x}{45}

\frac{18}{45}=\frac{x}{45}
18=x

In case of more complex fractions it may come in handy.

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The value of homes sold in Hampton VA are normally distributed with a mean of $200,000 and a standard deviation of $10,000. If 1

LenKa [72]

Answer:

84%

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

So for 190000 we have:

z = (190000 - 200000) / (10000)

z = -1

and this value represents 0.1587

for 230000 we have:

z = (230000 - 200000) / (10000)

z = 3

and this value represents 0.9987

we subtract: