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3 years ago

To which subsets of real numbers does the number -22 belong? Choose all subsets that apply. theres only 2 btw

Mathematics

2 answers:

Firlakuza [10]3 years ago

6 0

The 2 correct choices are 'a', 'b', and 'c'.

dimulka [17.4K]3 years ago

6 0

B,c
.................................

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He needs the height of the coop to be 2 feet shorter than the width and needs the length of the coop to be 10 feet longer than t

meriva

2feeet don’t understand what your asking

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3 years ago

Which graph shows the solution to the system of linear inequalities? y< 2x-5 y>-3x + 1

trapecia [35]

Answer:

See explanation

Step-by-step explanation:

Plot the solution sets to both inequalities.

1. For the inequality $y$ First, plot the dotted line $y=2x+5$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

$2\cdot 0-5=-5$

so the origin does not belong to the needed part. Shade the part, which does not include origin.

2. For the inequality $y>-3x+1.$ First, plot the dotted line $y=-3x+1$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

$-3\cdot 0+1=1>0$

so the origin does not belong to the needed part. Shade the part, which does not include origin.

3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.

5 0

3 years ago

Passes through (8,7) and (0,0)

quester [9]

Answer:

6,3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is 0.69696969 expressed as the quotient of two integers in simplest form?

timofeeve [1]

When written as the quotient of two integers,

 0.69696969 = 69,696,969 / 100,000,000 .

If you had said that the ' 69 ' keeps repeating forever and never ends,
then that decimal would represent the fraction
 23 / 33 .

3 0

3 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

4 years ago