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Bumek [7]
3 years ago
7

I know how to find the volume and height, but can't seem to find the radius. The answer I got was incorrect, but it's the only o

ne I keep getting. What would the answer be?

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0
I say 50 would be your answer
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Effectus [21]

Answer:

Step-by-step explanation:

3 0
3 years ago
A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5. Approximately how many studen
spin [16.1K]

Answer:  About 191 students scored between a 60 and an 80.

Step-by-step explanation:

Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.

i.e. \mu=70 and \sigma=5

let x be the random variable that denotes the test scores.

Then, the probability that the students scored between a 60 and an 80 :

P(60

The number of students scored between a 60 and an 80 = 0.9544 x 200

= 190.88 ≈ 191

Hence , about 191 students scored between a 60 and an 80.

8 0
4 years ago
By convention, the independent variable is arrayed along the ____ in a scattergram. regression line calibration line vertical ax
babunello [35]

Answer:

Horizontal axis

Step-by-step explanation:

By convention, the independent variables is arrayed along the Horizontal axis (abscissa) in a scattergram.

The stcattergram has two dimensions

  • The X (independent) variable is arrayed along the horizontal axis.
  • The Y(dependent) variable is arrayed along the vertical axis.
  • Each dot scattergram is case in data set.
  • The dot is placed at the intersection cases scores on X and Y.
7 0
3 years ago
FAST HURRY HELP PLZZ
Angelina_Jolie [31]

Answer:

I think its A but not 100 percent sure

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can anyone help me to understand how to solve coordinate proofs in Geometry?????
nataly862011 [7]

The coordinate proof is a proof of a geometric theorem which uses "generalized" points on the Cartesian Plane to make an argument.The method usually involves assigning variables to the coordinates of one or more points, and then using these variables in the midpoint or distance formulas .For example, the following is a coordinate proof of the Triangle Midsegment Theorem , which states that the segment connecting the midpoints of two sides of a triangle is parallel to the third side and exactly half the length.Without loss of generality, we can assume that one side of the triangle lies on the xx -axis with one vertex at (0,0)(0,0) and the other vertex at(a,0)(a,0).Let the third vertex have the coordinates (b,c)(b,c) . We can assume without loss of generality that this third vertex lies in the first quadrant. (If it doesn't, you can just reflect the triangle over the xx - and/or yy -axis until it does.)

Example:

To Prove: XY¯¯¯¯¯¯XY¯ is parallel to PR¯¯¯¯¯PR¯ and

<span><span>XY=<span>12</span>PR</span><span>XY=<span>12</span>PR</span></span>

Proof:

Using the midpoint formula , the coordinates of the midpoints XX and YY are

<span><span><span>X<span>(<span><span><span>0+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=X<span>(<span><span>b2</span>,<span>c2</span></span>)</span></span><span>Y<span>(<span><span><span>a+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=Y<span>(<span><span><span>a+b</span>2</span>,<span>c2</span></span>)</span></span></span><span><span>X<span>(<span><span><span>0+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=X<span>(<span><span>b2</span>,<span>c2</span></span>)</span></span><span>Y<span>(<span><span><span>a+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=Y<span>(<span><span><span>a+b</span>2</span>,<span>c2</span></span>)</span></span></span></span>

First note that the <span>slope </span>is <span>00</span> , since

<span><span><span>m=<span>riserun</span></span><span>     =<span><span>(<span><span>c2</span>−<span>c2</span></span>)</span><span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =<span>0<span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =0</span></span><span><span>m=<span>riserun</span></span><span>     =<span><span>(<span><span>c2</span>−<span>c2</span></span>)</span><span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =<span>0<span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =0</span></span></span>

So, <span><span><span>XY</span><span>¯¯¯¯¯¯</span></span><span><span>XY</span>¯</span></span> is parallel to <span><span><span>PR</span><span>¯¯¯¯¯</span></span><span><span>PR</span>¯</span></span> .

Now, compare the lengths of the two segments.

<span><span><span>XY=<span><span>a+b</span>2</span>−<span>b2</span></span><span>        =<span>a2</span></span><span>PR=a−0</span><span>        =a</span></span><span><span>XY=<span><span>a+b</span>2</span>−<span>b2</span></span><span>        =<span>a2</span></span><span>PR=a−0</span><span>        =a</span></span></span>

So,

<span><span>XY=<span>12</span>PR</span><span>XY=<span>12</span>PR</span></span>

Thanks to google for example


hope this helps

8 0
3 years ago
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