Question

Using the quadratic Formula to solve 2x^3=4x-7 what are the values of x

Answer 1

Answer:

$x=1(+/-)0.5i\sqrt{10}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}=4x-7$  

$2x^{2}-4x+7=0$  

so

$a=2\\b=-4\\c=7$

substitute

$x=\frac{4(+/-)\sqrt{(-4)^{2}-4(2)(7)}} {2(2)}$

$x=\frac{4(+/-)\sqrt{-40}} {4}$

Remember that

$i=\sqrt{-1}$

$x=\frac{4(+/-)2i\sqrt{10}} {4}$

$x=1(+/-)0.5i\sqrt{10}$