Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
<span>x=12 plus or minus the square root of 164 all divided by 2
or in decimal form </span>x = {12.403124237, -0.403124237}
Answer:
m = (y - y)/(x - x)
Rise/run
Step-by-step explanation:
Answer:
-120 , split it into diferent parts.
Step-by-step explanation:
12 (52) - 12 (62) = ?
12 x 52 = 624
12 x 62 = 744
624 - 744 = -120
Answer:
The hypotenuse is square root of 65
Step-by-step explanation:
a^2 + b^2 = c^2
legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.
4^2+7^2=16+49=65
c^2=65
Find the square root of both sides to get
c=the square root of 65
