Answer:
2) x = -2
, y = 2
3) no solution exists
Step-by-step explanation:
Solve the following system:
{-2 x - 3 y = -2
y = 2 x + 6
Hint: | Perform a substitution.
Substitute y = 2 x + 6 into the first equation:
{-2 x - 3 (2 x + 6) = -2
y = 2 x + 6
Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.
-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for x:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Isolate terms with x to the left hand side.
Add 18 to both sides:
{-8 x = 16
y = 2 x + 6
Hint: | Solve for x.
Divide both sides by -8:
{x = -2
y = 2 x + 6
Hint: | Perform a back substitution.
Substitute x = -2 into the second equation:
Answer: {x = -2
, y = 2
Answer:
1. Complex number.
2. Imaginary part of a complex number.
3. Real part of a complex number.
4. i
5. Multiplicative inverse.
6. Imaginary number.
7. Complex conjugate.
Step-by-step explanation:
1. <u><em>Complex number:</em></u> is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.
2. <u><em>Imaginary part of a complex number</em></u>: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.
3. <em><u>Real part of a complex number</u></em>: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.
4. <u><em>i:</em></u> a number defined with the property that 12 = -1.
5. <em><u>Multiplicative inverse</u></em>: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.
6. <em><u>Imaginary number</u></em>: any nonzero multiple of i; this is the same as the square root of any negative real number.
7. <em><u>Complex conjugate</u></em>: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.
Answer:I think 4/3
Step-by-step explanation:
5^2 +12^2= diagonal^2
25+144=d^2
169= d^2
D= 13
0.25 times r added to 0.6 times 6