Question

Which of the following equations has an infinite number of

Answer 1

The following equation has infinite many solutions

3(2x+1)=2(1+3x)+1

Step-by-step explanation:

An equation has infinite solutions if there is same constant on both sides of the equation.

We will check each equation one by one to find the equation with infinite solutions.

So,

3(2x+1)=2(1+3x)+1

$3(2x+1)=2(1+3x)+1\\6x+3 = 2+6x+1\\6x +3 = 6x +3\\6x-6x+3 = 3\\3 = 3$

3(2x+1)=2(1+3x)-1

$3(2x+1)=2(1+3x)-1\\6x+3 = 2+6x-1\\6x+3=1+6x\\6x-6x+3 = 1\\3 = 1$

3(2x-1)=2(1+3x)-1

$3(2x-1)=2(1+3x)-1\\6x-3 = 2+6x-1\\6x-3 = 1+6x\\6x-6x-3 = 1\\-3 = 1$

3(2x+1)=2(3+2x)-3​

$3(2x+1)=2(3+2x)-3​\\6x+3 = 6+4x-3\\6x+3 = 3+4x\\6x-4x+3 = 3\\2x+3 = 3$

The following equation has infinite many solutions

3(2x+1)=2(1+3x)+1

Keywords: Solution of equation, Linear equation

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