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2 years ago

Which of the following equations has an infinite number of

Mathematics

1 answer:

love history [14]2 years ago

6 0

The following equation has infinite many solutions

3(2x+1)=2(1+3x)+1

Step-by-step explanation:

An equation has infinite solutions if there is same constant on both sides of the equation.

We will check each equation one by one to find the equation with infinite solutions.

So,

3(2x+1)=2(1+3x)+1

$3(2x+1)=2(1+3x)+1\\6x+3 = 2+6x+1\\6x +3 = 6x +3\\6x-6x+3 = 3\\3 = 3$

3(2x+1)=2(1+3x)-1

$3(2x+1)=2(1+3x)-1\\6x+3 = 2+6x-1\\6x+3=1+6x\\6x-6x+3 = 1\\3 = 1$

3(2x-1)=2(1+3x)-1

$3(2x-1)=2(1+3x)-1\\6x-3 = 2+6x-1\\6x-3 = 1+6x\\6x-6x-3 = 1\\-3 = 1$

3(2x+1)=2(3+2x)-3

$3(2x+1)=2(3+2x)-3\\6x+3 = 6+4x-3\\6x+3 = 3+4x\\6x-4x+3 = 3\\2x+3 = 3$

The following equation has infinite many solutions

3(2x+1)=2(1+3x)+1

Keywords: Solution of equation, Linear equation

Learn more about linear equation at:

#LearnwithBrainly

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Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

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Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

$P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}$

$=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}$

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