Answer:
is represented in the graph.
Step-by-step explanation:
To find the linear inequality for the shown graph.
Steps:
Finding the equation of dotted line shown in the graph.
Equation of line is given by
where 
is slope of line and 
is y-intercept.
Given points: 
Slope of the line 
∴ 
From the given points we can see that point of y-intercept is given i.e. the point where the line intersects the y-axis 
∴ 
So equation of line:
Since the shaded area in the graph is above the line and the line is dotted this means that 
is greater than the equation of line.
So, the inequality can be given as:
Answer:
The correct option is option;
A. Flip
Step-by-step explanation:
When both sides of an inequality is divided by a negative number, it changes the sign of both numbers while their magnitude remain the same;
Therefore, if the right hand side of the inequality is lesser than the left hand side, when the signs of the left and right hand sides of the inequality changes after a division , by a negative number, we have;
The smaller right hand side of the inequality will then have a lesser negative magnitude than the left hand side of the inequality with a higher negative value and the left hand side (with the higher negative value) becomes lesser than the right and therefore, the symbol (sign) of the inequality is flipped
Therefore, when you divide both sides of an inequality by a negative number, you need to <u>flip</u> the inequality symbol.
Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
8 is the answer because you count up from the lower number
We are unable to answer this question without being able to see the graph.
