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3 years ago

What is the volume of a rectangular prism with the dimensions: base 2 3 /8 cm, height 1 1/3 cm, and length 3 3 /4 cm?

Mathematics

2 answers:

Ugo [173]3 years ago

5 0

Answer: 11.84 cm³

Step-by-step explanation:

1. Let's rewrite the given dimensions (expressed as mixed numbers) as decimals. Divide the numerator by the denominator of the fractional part and add the result to whole number part. Then:

$2^\frac{3}{8}cm=(2+0.375)cm=2.375cm\\1^\frac{1}{3}=(1+0.333)cm=1.333cm\\3^\frac{3}{4}=(3+0.75)cm=3.75cm$

2. Then, to calculate the volume you must multiply its dimensions. Therefore, you obtain the following result:

$V=2.375cm*3.75cm*1.33cm\\V=11.84cm^{3}$

padilas [110]3 years ago

5 0

Answer:

11 7/8

Step-by-step explanation:

decimals. Divide the numerator by the denominator of the fractional part and add the result to whole number part. Then:

2. Then, to calculate the volume you must multiply its dimensions. Therefore, you obtain the following result:

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3 years ago

A professor wants to know whether or not there is a difference in comprehension of a lab assignment among students depending on

san4es73 [151]

Answer:

It is concluded that no difference exists in the comprehension of the lab based on the test scores.

Step-by-step explanation:

Let the populations be normally distributed with a populations standard deviation of 5.32 points for both the text and visual illustrations.

The above statement tells us that the independent t or two sample t test will be performed as both have equal variances and are normally distributed.

This can be easily done through excel.

The following table is obtained

t-Test: Two-Sample Assuming Equal Variances

Text Visual Illustrations

Mean 70.28 75.08

Variance 304.48 228.58

Observations 15 15

Pooled Variance Sp²= 266.53

Pooled Standard Deviation = Sp = 16.33

Hypothesized Mean Difference = x1`-x2`= 0

df = n1+n2-2= 15+15-2= 30-2= 28

t Stat -0.805188239

P(T<=t) two-tail 0.427495979

t Critical two-tail 1.701130908

Let the null and alternate hypotheses be

H0 : u1-u2= 0 against the claim Ha: u1-u2≠0

There is no difference between the means

against the claim

that there is a difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

The significance level is ∝= 0.1

The d.f is n1+n2-2= 15+15-2= 30-2=28

This is a two tailed test and the critical region is t (0.025) (28) ≥ 1.7011 and t (0.025) (28) ≤ - 1.7011.

The test statistic is

t= x1-x2/ Sp √1/n1+ 1/n2

t= 70.28 -75.08/ 16.33√1/15 +1/15

t= -4.8/5.963

t= -0.8049811 ( minute difference from excel result due to rounding)

Since the calculated value of t= -0.8049 does not fall in the critical region we conclude that there is no difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

We accept the null hypothesis.

The p- value is 0.427495979.