The equation of the graph show is
y = -2/3x - 2
<span>What is the axis of symmetry for f(x)=5(x+7)(x-5)? Multiply out this polynomial to obtain the equation of a parabola in the form y = ax^2 + bx + c.
f(x) = 5(x^2 - 5x + 7x -35)
Holding the coefficient 5, we have 1x^2 - 2x - 35. Here a = 1 and b = -2, and
thus x = -b / (2a) provides the x-coord. of the axis of symm. It is:
x = -(-2) / (2*1) = 1.
The axis of symmetry is the vertical line x = 1.</span>
Answer:
<h3>

</h3>
Step-by-step explanation:

Move 7 to right hand side and change it's sign
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Add the numbers
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Divide both sides of the equation by 0.5
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Calculate
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Hope I helped!
Best regards!!
Looks like 14.4 because you have to add them all together and divide by the total numbers
(20+22+10+5+15)/ 5