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Allisa [31]
3 years ago
13

Andrea’s backyard is 400 square feet. Her rectangular swimming pool is 10 feet long, and six feet wide. What is the area of Andr

ea’s backyard, not including the swimming pool?
Mathematics
2 answers:
seraphim [82]3 years ago
5 0

Answer: The answer is 340

Step-by-step explanation:

You have to first find the area of the swimming pool 60 then you subtract it by the backyard 400 so you would get 340.

sashaice [31]3 years ago
4 0
First, you have to find the area of the rectangular swimming pool (A1), which has <span>10 feet long and 6 feet wide. The area of a rectangle is:

 A=A1=LxW

 L=10 ft
 W=6 ft

 When you substitute these values into the formula, you obtain:
</span>
 A1=LxW
 A1=(10 ft)(6ft)
 A1=60 ft²

 The area of the Andrea’s backyard (A2) is 400 ft², therefore, the<span> area of Andrea’s backyard, not including the swimming pool (A3), is:

 A3=A2-A1
 A3=400 ft</span>²-60 ft²
 A3=340 ft²
<span>
 What is the area of Andrea’s backyard, not including the swimming pool?

 The answer is: T</span>he area of Andrea’s backyard, not including the swimming pool, is 340 feet²
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Read 2 more answers
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<u>Answer:</u>

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Given, expression is m+\frac{2}{3}=\frac{1}{4 m}-1

Now, we have to solve the above given expression.

\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1

By multiplying the equation with m, we get

\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}

\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}

Now, let us use quadratic formula

\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in our problem, a = 12, b = 20, c = -3

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Hence the value of m is \frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6} by using quadratic formula

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If you want to learn more about domains, you can read:

brainly.com/question/1770447

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