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Virty [35]
3 years ago
8

3(n - 1) + 2n, when n = 5

Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0

Answer:

22

Step-by-step explanation:

<u>Substitute n with 5</u>

3(5-1) + 2(5)

<u>Simplify using order of operations (parentheses first, exponents next, multiplication after, then division, addition, and subtraction)</u>

3(4) + 10

12 + 10 = 22

<u>Answer</u>

22

babymother [125]3 years ago
7 0

Answer:22

Step-by-step explanation:3(5-1)+2(5)

3×4 +10

12+10=22

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The correct answer would be B
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Determine the general solution of:<br><br> sin 3x - sin x = cos2x
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we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
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Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
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Question 1 (5 points)
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Answer:

0.5 is the answer to this

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