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3 years ago

Can someone answer question number 39. For me. This is for 7th grade summer math and I sadly just don't get it.

Mathematics

2 answers:

iris [78.8K]3 years ago

8 0

The question is basically asking you to calculate the new volume of the box that is 12x 7.5 x 2.5inches and to see if it has a larger volume than 162.5 sqin.

If you calculate the volume you should get 225 square inches.

Viktor [21]3 years ago

5 0

The newer one has more volume because the original had 162.5 square inches and the new one has 225 square inches.

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Answer:

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2 years ago

A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct

KatRina [158]

<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

$Perimeter=2(L+\sqrt{100-L^2})$

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

$10=\sqrt{L^2+W^2}$

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

$10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}$

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

$W=\sqrt{100-L^2}$

Now, we know that the Perimeter of a rectangle is given by:

$Perimeter=2(L+W)$

Here we have:

$Perimeter=2(L+\sqrt{100-L^2})$

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3 years ago

A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?

avanturin [10]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a cone with base radius 9mm and height 13 mm

To calculate - volume of the cone

We know that ,

$Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h \\$

substituting the values in the formula ,

$Volume = \frac{1}{3} \times 3.14 \times 9 \times 9 \times 13 \\ \\ \implies \: 1.05 \times 81 \times 13 \\ \\ \implies \: 1105.65 \: mm {}^{3}$

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2 years ago

An engineer created a scale drawing of a building using a scale in which 0.25 inch represents 2 feet. The length of the actual b

Nady [450]

The length of the building in the scale drawing is 31. 25 Inches

<h3>How to determine the value</h3>

From the information given, we have that;

Scale drawing was used
0. 25 inches represents 2 feet
The length of the building is 250 feet

Then,

If 0. 25 inches = 2 feet

Then x inches = 250 feet

cross multiply
x × 2 = 0. 25 × 2500

Multiply through, we have;

2x = 62. 5

Make 'x' the subject by dividing both sides by 2

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Thus, the length of the building in the scale drawing is 31. 25 Inches

Learn more about scale drawing here:

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