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3 years ago

Can someone answer question number 39. For me. This is for 7th grade summer math and I sadly just don't get it.

Mathematics

2 answers:

iris [78.8K]3 years ago

8 0

The question is basically asking you to calculate the new volume of the box that is 12x 7.5 x 2.5inches and to see if it has a larger volume than 162.5 sqin.

If you calculate the volume you should get 225 square inches.

Viktor [21]3 years ago

5 0

The newer one has more volume because the original had 162.5 square inches and the new one has 225 square inches.

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find the perimeter of an isosceles triangle with side lengths of 5+x, 5+x, and xy. Write in simplest form.

Zinaida [17]

<h3>Answer: perimeter = 10+2x+xy</h3>

To get the perimeter, you add up all the outer sides

side1+side2+side3 = (5+x)+(5+x)+(xy) = 10+2x+xy

The like terms 5 and 5 add to 10. The other pair of like terms x and x add to 2x. There isn't anything to pair with xy, so we leave it as is.

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3 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

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3 years ago

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Nastasia [14]

Answer:ill have to see

Step-by-step explanation:

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Igoryamba

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