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3 years ago

To give your app users the ability to open your app directly from other apps by clicking a link, you should use:.

1 answer:

7 0

To give your app users the ability to open your app directly from other apps by clicking a link, you should use: deep link. With the deep link and its URL functionality, existing app users are driven directly inside the mobile app itself.
Deep links are usually made up of two parts: a scheme (part of the link that identifies which app to open).and a host and path (the unique location in the app where your content exists).

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Develop a script to demonstrate an understanding of the overload (overwrite) methods of using Python operators. This lesson will

MrRa [10]

hsjshekejeoehejeoejebenwkwuwbnwlwjdvrbrnfnfjkddjddmdmdndnfndmdkdjdjdjdjjdjdjdjdkdkdkdkdfkkdjdjdjdyremssjyehsmmamaajbshsjsbdbsksidhdbdbddddddddododododkdkdkdjdjdhddhhdvxbxbbxbxbxjdiegebeodhe

8 0

3 years ago

Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following string

Artist 52 [7]

Answer:

#include <bits/stdc++.h>

using namespace std;

bool isPalindrome(string str)

{

char a,b;

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

a=tolower(str[i]);//Converting both first characters to lowercase..

b=tolower(str[length-1-i]);

if (b != a )

return false;

}

return true;

}

int main() {

string t1;

cin>>t1;

if(isPalindrome(t1))

cout<<"The string is Palindrome"<<endl;

else

cout<<"The string is not Palindrome"<<endl;

return 0;

}

Output:-

Enter the string

madam

The string is Palindrome

Enter the string

abba

The string is Palindrome

Enter the string

The string is Palindrome

Enter the string

67876

The string is Palindrome

Enter the string

444244

The string is not Palindrome

Explanation:

To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.

6 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago

Which of the items below are nodes? fax, IC, NOC, printer, twisted pair cables and workstation.

RSB [31]

The answer is Printer, workstation, NOC, and fax.

Any devices or systems connected to a network are called nodes. When defining a node, always have in mind that it is anything that has an IP address. For instance, if a network connects 5 computers, 1 file server, and 2 printers, there are 8 nodes on this network.

3 0

3 years ago

What is the main difference between EDBAC and EDNIAC......

lawyer [7]

Answer:

EDVAC (Electronic Discrete Variable Automatic Computer) was the successor to ENIAC, was binary based, and used stored programs, and was also designed by Eckert and Mauchly, UNIVAC I (UNIVersal Automatic Computer I) was the first commercial computer. It was designed by the same two men who designed ENIAC and EDVAC.

Explanation:

6 0

3 years ago

Read 2 more answers