Answer:
The volume of a bar of gold with a mass of 66.5 grams is 
Step-by-step explanation:
Given , mass(in grams) ∝ Volume (in cm3)
Here, volume of 95 grams bar = 5cm3
So, thevolume of 1 gram bar =
= 
⇒The volume of a bar with weight 66.5 grams = 
So, the volume of a bar of gold with a mass of 66.5 grams is 
The product is 56x^3+62x^2-44x-14
Answer:
k and l....................
Answer:
A
Step-by-step explanation:
There are two ways you could do this question. You could graph it with something like Desmos or you could put a couple of x values in for f(x). I'll do the latter first. When you understand it, try putting it into Desmos.
f(x) = (3/4)^x
f(0) = (3/4)^0
f(0) = 1
=======
f(x) = (3/4)^x
f(1) = 3/4
=========
g(x) = (3/4)^x - 6
g(0) = (3/4)^0 - 6
g(0) = 1 - 6
g(0) = - 5
========
g(x) = (3/4)^x - 6
g(1) = (3/4)^1 - 6
g(1)= 3/4 - 6
g(1) = -5 1/4
Conclusion
It looks like the graph has shifted down 6.
Answer
A
Answer:
8 tickets
Step-by-step explanation:
x = 10 in the given equation.
We have then:
C (x) = 17.5x - 10
C (10) = 17.5 * (10) - 10
C (10) = 165
Answer:
to buy 10 tickets cost:
$ 165
b. How many tickets can you buy with $ 130?
For this case we must make the substitution: C (x) = 130
We have then:
C (x) = 17.5x - 10
130 = 17.5x - 10
Clearing x we have:
17.5x = 130 + 10
17.5x = 140
x = (140) / (17.5)
x = 8
Answer:
You can buy 8 tickets with $ 130