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2 years ago

13

What is one sixth of 2.00

1 answer:

uysha [10]2 years ago

6 0

If I’m not mistaken it should be 0.33

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1 Solve for the unknown variable:

Burka [1]

Answer:

Approximately 6.4

Step-by-step explanation:

We can use the pythagorean thereom here, that tells us (a^2)+(b^2)=c^2. C is the hypotenuse, the side opposite from the right angle, while a and b are the other sides. We can insert 5 and 4 as a and b, and solve for c

:(5^2)+(4^2)=c^2

:25+16=c^2

:41=c^2

:sqrt(41)=6.4=c (We square rooted both sides. 6.4 is only rounded to the nearest hundredths place.) Hope this helps!

8 0

2 years ago

Read 2 more answers

A city police officer using radar checked the speed of 26 cars as they were travelling down a city street and the data is given

pychu [463]

Answer: The distribution of the data set is positively skewed.

<u>Explanation: </u>

In order to see whether the given data set is symmetric, positively skewed or negatively skewed, we will find the mean, median and mode of the given data set.

For symmetric distribution, $Mean = Median=Mode$

For positively skewed distribution, $Mean > Median>Mode$

For negatively skewed distribution, $Mean < Median$

The mean of the given data set is given below:

$Mean = \frac{27+23+22+38+43+24+25+23+22+54+31+30+29+48+27+25+29+28+26+33+25+21+23+34+20+23}{26}$

$=\frac{753}{26}$

$=28.96$

Now, the Median is:

To find the median we need to sort the data in ascending order as:

$20,21,22,22,23,23,23,23,24,25,25,25,26,27,27,28,29,29,30,31,33,34,38,43,48,54$

$Median=\left(\frac{N+1}{2} \right)^{th} item$

$=\left(\frac{26+1}{2}\right)^{th} item$

$=13.5^{th} item$

$=26+0.5 \times (27-26)$

$=26.5$

$\therefore Median = 26.5$

The mode is the most frequently occurring observation. Therefore the mode is:

$Mode=23$

Since the $Mean >Median>Mode$ , therefore the distribution of the given data set is positively skewed.

5 0

4 years ago

If m=2,n=5 and y =3, evaluate

svlad2 [7]

Answer:

here you go :)

Step-by-step explanation:

Replace the variables with their corresponding values:

$\frac{2(5+3)}{2*5}$

Cancel out 2 in both numerator and denominator.

$\frac{3+5}{5}$

Add 3 and 5 to get 8.

$\frac{8}{5}$

Finally, divide 8 by 5 to get your answer:

$\frac{8}{5} = 1.6$

Your answer is (a) 1.6

<h2>Hope this helps! :)</h2>

3 0

2 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

Help I don’t know the answer

Marrrta [24]

Answer:

15 ft

Step-by-step explanation:

cause

24/8=3

5×3=15

6 0

3 years ago