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Nataliya [291]
3 years ago
7

(a) Consider a carbon atom in its ground state. Would such an atom offer a satisfactory model for the carbon of methane? If not,

why not? (Hint: Consider whether a ground state carbon atom could be tetravalent, and consider the bond angles that would result if it were to combine with hydrogen atoms.)
(b) Consider a carbon atom in the excited state. Would such an atom offer a satisfactory model for the carbon of methane? If not, why not?

Chemistry
1 answer:
viva [34]3 years ago
7 0

Answer:

(a) No. Ground-state carbon has only 2 half-filled orbitals that could be used for bonding.

(b) No. The bond angles would be incorrect as the p-orbitals are all perpendicular to each other (90°).

Explanation:

See attachment for the ground-state and excited-state electron orbital diagrams of carbon.

A methane molecule has all four CH bonds the same length and at 109.5° from each other. Hybridization of the s and p orbitals to sp³ orbitals is necessary.

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Answer:

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Explanation:

Nitrogen dioxide is a chemical compound with the formula NO 2.It is one of several nitrogen oxides. NO 2 is an intermediate in the industrial synthesis of nitric acid, millions of tons of which are produced each year for use primarily in the production of fertilizers.At higher temperatures it is a reddish-brown gas.

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What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2
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The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

Learn more about Avogadro's number:

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0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the co
grigory [225]

Answer:

No results found for 0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the constituent elements are 92.24% C and 7.76% H. Find the molecular mass and molecular formula of the composition..

Results for 0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg Percentage composition of the constituent elements are 92.24 C and 7.76 H Find the molecular mass and molecular formula of the composition

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