Construct the inequality for the following cases.

Match each interaction type to the correct amount of potential energy.

Zigmanuir [339]

The type of energy which is present between the repulsion interaction is the highest potential energy.

<h3>What is potential energy?</h3>

Potential energy is the amount of energy that is possess by any body with respect to the electric charge posses in that and other factors also.

When molecules have a high attraction force then they have the low potential energy in them.
When molecules have a great repulsion between them then they have the great potential energy in them.
And molecules have the middle amount of potential energy then they have the balanced interaction.

Hence, molecules in which repulsion interaction is present will have highest potential energy.

To know more about potential energy, visit the below link:

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3 0

2 years ago

) determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a

Nataly [62]

Answer:

a. 59 m/atm

Explanation:

To solve this problem, we must mention Henry's law.

<em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>

It can be expressed as: C = KP,

C is the concentration of the solution (C = 1.3 M).

P is the partial pressure of the gas above the solution (P = 0.022 atm).

K is the Henry's law constant (K = ??? M/atm),

∵ C = KP.

∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.

3 0

3 years ago

When are conservation efforts most effective? a. Conservation efforts are most effective when multiple groups cooperate. b. Cons

alexandr402 [8]

Conservation efforts most effective if <span>Conservation efforts are most effective when multiple groups cooperate. The answer is letter A. The rest of the choices do not answer the question above</span>

7 0

4 years ago

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A slender uniform rod 100.00 cm long is used as a meter stick. two parallel axes that are perpendicular to the rod are considere

kvv77 [185]

Refer to the diagram shown below.

The second axis is at the centroid of the rod.
The length of the rod is L = 100 cm = 1 m

The first axis is located at 20 cm = 0.2 m from the centroid.
Let m = the mass of the rod.

The moment of inertia about the centroid (the 2nd axis) is
$I_{g} = \frac{mL^{2}}{12} = (m \, kg) \frac{(1 \, m)^{2}}{12} = \frac{m}{12} \, kg-m^{2}$

According to the parallel axis theorem, the moment of inertia about the first axis is
$I_{1} = I_{g} + (m \, kg)(0.2 m)^{2} \\ I_{1} = \frac{m}{12}+ 0.04m = 0.1233m \, kg-m^{2}$

The ratio of the moment of inertia through the 2nd axis (centroid) to that through the 1st axis is
$\frac{I_{g}}{I_{1}} = \frac{0.0833m}{0.1233m} =0.6756$

Answer: 0.676

6 0

3 years ago

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What is the molecular geometry around each carbon atom in a saturated hydrocarbon?

Lelu [443]

Answer:
<span>Molecular geometry around each carbon atom in a saturated hydrocarbon is Tetrahedral.

Explanation:
</span> In saturated hydrocarbons (-CH₂-) the central atom (carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to Valence Shell Electron Pair Repulsion (VSEPR) Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a tetrahedral geometry with bond angles of 109°.

7 0

3 years ago

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