1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeTakaya
3 years ago
12

Choose all the answers that apply. Lakes are recharged by _____. 1.evaporation 2.precipitation 3.rivers 4.transpiration 5.ground

water seepage 6.melting snow and ice
Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
6 0
2. Precipitation, because when it rains the water that was taken when it was evaporated is replaced and it fills the lake back up
julsineya [31]3 years ago
6 0
THE ANSWER IS PRECIPITATION. PRECIPITATION IS RAIN. EVERY TIME IT RAINS, EVERY BODY OF WATER IS INVOLVED IN THIS PROCESS. THE OCEAN, LAKES, PONDS, ETC
You might be interested in
All objects in space obey the law of ________.
Lera25 [3.4K]

Answer:

physics, including the laws of gravity

Explanation:

7 0
3 years ago
Can someone help me please
Nostrana [21]
The answer is a as it is balanced and has the shown molecules
6 0
3 years ago
According to the law of conservation of mass, how does the mass of the products in a chemical reaction compare to the mass of th
fgiga [73]
D. The masses are always equal.
3 0
3 years ago
What is the frequency of a radio wave with a a wavelength of 3 m? (Hint: MHz
Ostrovityanka [42]

Answer:
a. 1 x 10^8

Explanation:

100 MHz = 100,000,000 Hz = 10^8 Hz

4 0
2 years ago
Write the equilibrium constant expression for this reaction: 2H+(aq)+CO−23(aq) → H2CO3(aq)
MrRissso [65]

Answer:

Equilibrium constant expression for \rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq) \rightleftharpoons H_2CO_3\, (aq):

\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{[\mathrm{H_2CO_3}]}{\left[\mathrm{H^{+}\, (aq)}\right]^{2} \, \left[\mathrm{CO_3}^{2-}\right]}.

Where

  • a_{\mathrm{H_2CO_3}}, a_{\mathrm{H^{+}}}, and a_{\mathrm{CO_3}^{2-}} denote the activities of the three species, and
  • [\mathrm{H_2CO_3}], \left[\mathrm{H^{+}}\right], and \left[\mathrm{CO_3}^{2-}\right] denote the concentrations of the three species.

Explanation:

<h3>Equilibrium Constant Expression</h3>

The equilibrium constant expression of a (reversible) reaction takes the form a fraction.

Multiply the activity of each product of this reaction to get the numerator.\rm H_2CO_3\; (aq) is the only product of this reaction. Besides, its coefficient in the balanced reaction is one. Therefore, the numerator would simply be \left(a_{\mathrm{H_2CO_3\, (aq)}}\right).

Similarly, multiply the activity of each reactant of this reaction to obtain the denominator. Note the coefficient "2" on the product side of this reaction. \rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq) is equivalent to \rm H^{+}\, (aq) + H^{+}\, (aq) + {CO_3}^{2-}\, (aq). The species \rm H^{+}\, (aq) appeared twice among the reactants. Therefore, its activity should also appear twice in the denominator:

\left(a_{\mathrm{H^{+}}}\right)\cdot \left(a_{\mathrm{H^{+}}}\right)\cdot \, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right = \left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right.

That's where the exponent "2" in this equilibrium constant expression came from.

Combine these two parts to obtain the equilibrium constant expression:

\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \quad\begin{matrix}\leftarrow \text{from products} \\[0.5em] \leftarrow \text{from reactants}\end{matrix}.

<h3 /><h3>Equilibrium Constant of Concentration</h3>

In dilute solutions, the equilibrium constant expression can be approximated with the concentrations of the aqueous "(\rm aq)" species. Note that all the three species here are indeed aqueous. Hence, this equilibrium constant expression can be approximated as:

\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{\left[\mathrm{H_2CO_3\, (aq)}\right]}{\left[\mathrm{H^{+}\, (aq)}\right]^2\cdot \left[\mathrm{{CO_3}^{2-}\, (aq)}\right]}.

8 0
3 years ago
Other questions:
  • The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 2.69 × 1012 at 25°c. calculate e o for a cell m
    12·1 answer
  • An aqueous magnesium chloride solution is made by dissolving 6.90 moles of MgCl 2 in sufficient water so that the final volume o
    12·1 answer
  • Accounting Concepts Should we buy stock in a company? Should we extend a line of credit to a company? Should we continue with cu
    14·1 answer
  • How any electrons are shared in the covalent bond of two nitrogen atoms to form a nitrogen molecule?
    14·1 answer
  • What must be the specific heat of a sample of an unknown material of 36.359g,when 59.912J of heat are applied raising the temper
    8·1 answer
  • An apple plant has two dominant alleles for red apples, RR. If it is crossed with another plant that has recessive genes for gre
    6·2 answers
  • Name the five methods used for the formation of salts??
    7·1 answer
  • Magnesium has three naturally occurring isotopes with masses of 23.99 amu, 24.99 amu, and 25.98 amu and natural abundances of 78
    13·1 answer
  • Generating energy through combustion of renewable biofuels that cause
    12·1 answer
  • Working with a strong acid, such as sulfuric or nitric acid, requires special care to strictly avoid contact with the acid. What
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!