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3 years ago

What is the perimeter of rectangle with vertices located at (- 3, - 1), (5, - 1), (5, 9) and (- 3, 9) on the coordinate ?

Mathematics

1 answer:

xxMikexx [17]3 years ago

3 0

Answer:

32 units^2

Step-by-step explanation:

Finding the width and the length:

One side = √[(-1 - (-1)^2 + (5 - (-3))^2]

= √(0 + 64)

= 8.

The adjacent side = √(9-9)^2 + (-3-5)^2

= 8.

Perimeter - 4 *8 = 32 units^2.

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Answer:

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3 years ago

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3 years ago

Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

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3 years ago