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oksano4ka [1.4K]
3 years ago
8

What is the perimeter of rectangle with vertices located at (- 3, - 1), (5, - 1), (5, 9) and (- 3, 9) on the coordinate ?

Mathematics
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

32 units^2

Step-by-step explanation:

Finding the width and the length:

One side = √[(-1 - (-1)^2 + (5 - (-3))^2]

= √(0 +  64)

= 8.

The adjacent side = √(9-9)^2 + (-3-5)^2

= 8.

Perimeter - 4 *8 = 32 units^2.

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What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t
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\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}

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\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:

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1 year ago
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