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oksano4ka [1.4K]
3 years ago
8

What is the perimeter of rectangle with vertices located at (- 3, - 1), (5, - 1), (5, 9) and (- 3, 9) on the coordinate ?

Mathematics
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

32 units^2

Step-by-step explanation:

Finding the width and the length:

One side = √[(-1 - (-1)^2 + (5 - (-3))^2]

= √(0 +  64)

= 8.

The adjacent side = √(9-9)^2 + (-3-5)^2

= 8.

Perimeter - 4 *8 = 32 units^2.

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Find the area of the rectangle
castortr0y [4]

Step-by-step explanation:

Length (L) = 2 cm

Breadth (b) = 2 / 3 cm

Area of the rectangle

= L * b

= 2 * 2/3

= 4/3 cm²

Hope it will help :)❤

6 0
3 years ago
Which is Bigger y=6x+4, or y=3(x)+ 2
antoniya [11.8K]
Y=6x is bigger because they have the same variables, but the known numbers in the first equation are doubled
5 0
3 years ago
What is the solution to this problem
Nuetrik [128]
Hello Again! The answer would be C. (8,11)
To confirm we will plug the numbers x = 8, Y = 11
------------------------
2x - 5 = y
(2 x 8) - 5 = 11
16 - 5 = 11
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8 0
3 years ago
Having a small brain moment, can you please help and show work
ankoles [38]

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

0.5(2x +  \frac{3}{4} ) -  \frac{1}{3} (0.1 + x) = 1

0.5(2x) + 0.5( \frac{3}{4} ) -  \frac{1}{3} (0.1) -  \frac{1}{3} (x) = 1

x +  \frac{3}{8}  -  \frac{1}{30}   -   \frac{1}{3} x = 1

Next you have to collect like terms :

x  -  \frac{1}{3} x +  \frac{3}{8}  -  \frac{1}{30}  = 1

\frac{2}{3} x +  \frac{41}{120}  = 1

Lastly, you can solve x :

\frac{2}{3} x = 1 -  \frac{41}{120}

\frac{2}{3} x =  \frac{79}{120}

x =  \frac{79}{120}  \div  \frac{2}{3}

x =  \frac{79}{80}

x = 0.9875

8 0
3 years ago
Verbal expression for 4x^5
dsp73
4 multiplied by x to the power of five
3 0
3 years ago
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