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Lesechka [4]
3 years ago
14

Having a small brain moment, can you please help and show work

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

0.5(2x +  \frac{3}{4} ) -  \frac{1}{3} (0.1 + x) = 1

0.5(2x) + 0.5( \frac{3}{4} ) -  \frac{1}{3} (0.1) -  \frac{1}{3} (x) = 1

x +  \frac{3}{8}  -  \frac{1}{30}   -   \frac{1}{3} x = 1

Next you have to collect like terms :

x  -  \frac{1}{3} x +  \frac{3}{8}  -  \frac{1}{30}  = 1

\frac{2}{3} x +  \frac{41}{120}  = 1

Lastly, you can solve x :

\frac{2}{3} x = 1 -  \frac{41}{120}

\frac{2}{3} x =  \frac{79}{120}

x =  \frac{79}{120}  \div  \frac{2}{3}

x =  \frac{79}{80}

x = 0.9875

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Which statements are true when using algebra tiles to solve the equation 8x + (–4) = 11x + 5?
kogti [31]

Answer:

See explanation

Step-by-step explanation:

You are given the equation 8x+(-4)=11x+5

1. Add 8 negative x-tiles to both sides of the equation to create a zero pair on the left side. The equation then will have form

8x+(-4)+(-8x)=11x+5+(-8x)\\ \\-4=3x+5

2. Add 5 negative unit tiles to both sides of the equation to create a zero pair on the right side. The equation now is

-4+(-5)=3x+5+(-5)\\ \\-9=3x

3. Divide both sides by 3:

\dfrac{3x}{3}=\dfrac{-9}{3}\\ \\x=-3

7 0
3 years ago
Read 2 more answers
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
Please help with this
Maksim231197 [3]

Answer:

Choice A

Step-by-step explanation:

  • SSS is not applicable as only 2 sides are congruent
  • HL is lot applicable as triangles are not right angled (∠A and ∠E >90)
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nadya68 [22]

Answer:

its positive

Step-by-step explanation:

because the line going upward

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Simplify each expression.
Vlad [161]

Answer:

The answer is:

32x+12y

Step-by-step explanation:

Because 4 times 8 =32 and 4 times 3 =12

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