Answer: You should get 0.68 back
Step-by-step explanation: I just did a test and got 100%
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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Answer:
Step-by-step explanation:
Given
Required
The new coordinates after reflected across y-axis and shifted 2 units down
When a point is reflected across the y-axis, the rule is:
So:
When a point is translated 2 units down, the rule is:
So:
So, the new coordinates are:
91.5 is the perimeter. It's just 5a.
I Belive it might be ballad
