Answer:
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
Step-by-step explanation:
IQR = Q₃ - Q₁
For the town A:
Q₃ = 40 and Q₁ = 20
IQR of town A = 40 - 20 = 20
For the town B:
Q₃ = 30 and Q₁ = 20
IQR of town A = 30 - 20 = 10
Check the given options:
The most statement is appropriate comparison of the spreads is B
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
<u />
Angle in a semi circle is 90°
<a = 180-90-<b = 90-28 = 62°
opposite angles of a cyclic quadrilateral sums up to 180°
<b + <a = 180
<b = 180-62
<b = 118°
Answer:
A) 5
Step-by-step explanation:
The coefficients of the second equation are 1/3 of those of the first equation. If the constant of the second equation is also 1/3 of the constant of the first equation, then the equations are <em>dependent</em>, and will have an infinite number of solutions.
The constant must be something other than 1/3·15 = 5 to make the equations <em>inconsistent</em>, having no solutions.
Answer:
None of the options are correct, as the answer is <u>2x - 18 = 68.</u>
Step-by-step explanation:
The <u>2x</u> represents the length (x) being half of the width (68)
The <u>-18</u> represents the width (68) being 18 less than twice the length (2x)
Hello there!
By a over 6, I assume you mean a / 6? And by the wording, I assume 3 is outside of the fraction.
For the three outside the fraction,
(a / 6) + 3
(48 / 6) + 3
8 + 3
= 11
Hoped this help! If you have any more questions or need any more assistance, don't hesitate to friend me and message me! I can provide a mini lesson and a in-depth explanation as to what I did and why.
