Answer: 210
Explanation: To find the least common multiple for the integers 30 and 35, we start by making a factor tree for each of our integers.
So 30 is 10 · 3 and 10 is 5 · 2.
35 is 7 · 5.
Notice that our 5's match up as factors of each of our integers.
When finding the least common multiple, we simply multiply all of our factors together but since the 5's match up,
we only multiply by a 5 once.
So our least common multiple or LCM is
5 · the 2 that doesn't match up · the 3 that
doesn't match up · the 7 that doesn't match up.
So we have 5 · 2 · 3 · 7 or 210.
Work is shown below.
Answer: -39c-12
Step-by-step explanation:
Answer: the diameter of the can is 2.8 inches
Step-by-step explanation:
The formula for determining the volume of a cylinder is expressed as
Volume = πr²h
Where
r represents the radius of the cylinder.
h represents the height of the cylinder.
π is a constant whose value is 3.14
From the information given,
height = 4.5 inches
Volume of can = 454 millilitres
1 cubic inch = 16.387 millilitres
Converting 454 millilitres to cubic inches, it becomes
454/16.387 = 27.7 cubic inches
Therefore
27.7 = 3.14 × r² × 4.5
27.7 = 14.13r²
r² = 27.7/14.13
r² = 1.96
r = √1.96
r = 1.4
Diameter = 2 × radius
Diameter = 2 × 1.4 = 2.8 inches
Considering the given area of the square, it is found that it's side length is an irrational number.
<h3>What is the missing information?</h3>
This problem is incomplete, but researching it on a search engine, it asks if the side length of the square of area 89 cm² is rational or irrational.
<h3>What is the formula for the area of a square?</h3>
The area of an square of side length s is given by s squared, as follows:
A = s².
In this problem, the area is of 89 cm², hence:
s² = 89.
s = sqrt(89).
The square root of 89 is a non-exact root, hence it cannot be represented by fraction and is an irrational number.
More can be learned about the area of a square at brainly.com/question/10489198
#SPJ1
Answer:
4 apples
Step-by-step explanation:
You subtract 1 from 5 and get how many apples you have.
