Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
9.25
Step-by-step explanation:
8|74.00
-72
20
- 16
40
- 40
00
Answer:
$4500
Step-by-step explanation:
$350 x 10 = 3500 + 1000 which ends up with a total of $4500. I hope this helped :)
Answer:
1024pi cm²
Step-by-step explanation:
4pi(16)²
4pi256
1024pi
2^3 = 8
11/9 = 1.22
sqrt 5 = 2.24
sqrt 20 = 4.47
sqrt 11 = 3.32
least to greatest : 11/9, sqrt 5 , sqrt 11 , sqrt 20, 2^3