(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) h(3)=
2 answers:
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Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a.
b.
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:
The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days
Solving (b); The value of E when d = 30.
Substitute 30 for d in
<em>Hence, there are 5000kwh left after 30 days</em>
Answer: First Option is correct.
Step-by-step explanation:
Since we have given that
Number of hours Chance can wash the car = 2 hours
Number of hours Sandy can wash the car = 4 hours
Work done by Chance per hour is given by
Work done by Sandy per hour is given by
Work done by altogether per hour is given by
So, Number of hours they take if they together wash the car is given by
Hence, First Option is correct.