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3 years ago

(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) h(3)=

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

Answer:

Step-by-step explanation:

nalin [4]3 years ago

5 0

Answer:

Step-by-step explanation:

h(3)=h(1)*h(2)=

(-10)*(-2)=

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In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what

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Answer:

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Step-by-step explanation:

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see the attached figure to better understand the problem

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(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) ​ h(3)=

(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) h(3)=