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astra-53 [7]
3 years ago
11

Solve the equation 5x-2x^2+1

Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

Step-by-step explanation:

If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:

5x-2x^2+1 = 0

This is a quadratic equation.  Rearranging the terms in descending order by powers of x, we get:

-2x^2 + 5x + 1 = 0.  Here the coefficients are a = -2, b = 5 and c = 1.

Use the quadratic formula to solve for x:

First find the discriminant, b^2 - 4ac:  25 - 4(-2)(1) = 25 + 8 = 33

Because the discriminant is positive, the roots of this quadratic are real and unequal.

                                                             -b ± √(discriminant)

Applying the quadratic formula   x = --------------------------------

                                                                         2a

we get:

      -5 ± √33           -5 + √33

x = ----------------- = --------------------- and

           2(-2)                     -4

                                  -5 - √33

                                 ---------------

                                         -4

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if you deposit $15 a week into the savings account what is the minimum number of weeks it will take for you to be able to open a
castortr0y [4]

Answer:

15 weeks

15 times 15 is 225

$200 (checking) $25 (savings)

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8 0
3 years ago
A shirt normally cost 26 pounds. the price was reduced by 25%. how much does the shirt cost now?
GarryVolchara [31]

Answer:

19.5 pounds

Step-by-step explanation:

25% of 26 equals 6.5, so 26-6.5 is 19.5 pounds

6 0
3 years ago
The scale on a map is 5.1 cm : 2 mi. Find the distance in miles between two cities that are 12 centimeters apart on the map. Rou
Lyrx [107]
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3 0
3 years ago
The growth of a local raccoon population approximates a geometric sequence where f(n) is the number of raccoons in a given year
Luda [366]

Answer:

f(n) = 14.3908 * 1.2561^(n-1)

Step-by-step explanation:

A geometric sequence can be defined by:

f(n) = a*r^(n-1), where 'a' is the inicial population, and 'r' is the ratio the population increases each year

If we have 45 raccoons after 6 years and 71 raccoons after 8 years, we can use these values in the equation to find the values of 'a' and 'r':

for n=6, f(n) = 45:

45 = a*r^5

for n=8, f(n) = 71:

71 = a*r^7

dividing the second equation by the first, we have:

r^2 = 71/45 = 1.5778

r = 1.2561

Now, applying this value of 'r' in the first equation, we find 'a':

45 = a*1.2561^5

a = 45/3.1270 =  14.3908

So, the function that models the local raccoon population 'f(n)' in the terms of the number of years 'n' is:

f(n) = 14.3908 * 1.2561^(n-1)

6 0
3 years ago
1 3<br> -- _ = _ y<br> 2 8<br> Please help me
SOVA2 [1]
(If you are)- Solving The Equation

1. Multiply both sides by eight over three

8/3•1/2 = 8/3•3/8 which gives you 4/3.


2. Swap the sides of the equation

4/3=y turns into y= 4/3 and that’s your answer. (y=4/3).

(Or if you’re working on)- Rewrite In Standard Form

Swap 1/2 and 3/8y , so it should be 3/8y=1/2.

Then multiply both sides by 8/3, and that should give you y=4/3.

Then multiply both sides of the equation by 3, and that should give you 3y = 4. And 3y=4 would be your answer.


Hope these helped! :)
6 0
3 years ago
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