All categories

3 years ago

Solve the equation 5x-2x^2+1

Mathematics

1 answer:

Pani-rosa [81]3 years ago

5 0

Answer:

Step-by-step explanation:

If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:

5x-2x^2+1 = 0

This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:

-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.

Use the quadratic formula to solve for x:

First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33

Because the discriminant is positive, the roots of this quadratic are real and unequal.

-b ± √(discriminant)

Applying the quadratic formula x = --------------------------------

we get:

-5 ± √33 -5 + √33

x = ----------------- = --------------------- and

2(-2) -4

-5 - √33

---------------

-4

You might be interested in

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

7 0

3 years ago

You owe your sister $5.35, and she lends you another $4.50, how much do you owe her now

Margarita [4]

You would now have to pay her $9.85

6 0

3 years ago

F(x) = x2 + 1 g(x) = 5-x (f+g)(x) = O x2 + x-4 x²+x+4 O x2-x+6 O x2 + x + 6

charle [14.2K]

Answer:

$\boxed{(f + g)(x) = {x}^{2} - x + 6}$

Given:

$f(x) = {x}^{2} + 1 \\ \\ g(x) = 5 - x$

To Find:

$(f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$= > f(x) + g(x) = ({x}^{2} + 1) + (5 - x) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 1 + 5 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 6 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - x + 6$

5 0

3 years ago

Explain how proving to triangles congruent can help prove parts of the triangle congruent.

nydimaria [60]

Answer:

CPCTC - Corresponding Parts of Congruent Triangles are Congruent

Step-by-step explanation:

When two triangles are congruent, this means they have the same shape and the same size. To have the same shape, each angle must be congruent. To have the same size, each side length must be congruent. When you know two triangles are congruent you can say each corresponding part of congruent triangles is congruent. This is known as CPCTC.

7 0

3 years ago

assuming that no questions are left unanswered, in how many ways can a six-question quiz with 4-choice multiple choice questions

AfilCa [17]

Given:

Total number of questions = 6

Choice for each question (in MCQ) = 4

Assuming that no questions are left unanswered.

To find:

The total number ways to answer the quiz, assuming that no questions are left unanswered.

Solution:

Here, Number of ways to answer each question = 4

To find the total number ways to answer 6 MCQ, we have to have to multiply number of ways to answer each question 6 times.

Total number of ways to answer six-question quiz with 4-choice multiple choice questions is

$4\times 4\times 4\times 4\times 4\times 4=4096$

Therefore, the required number of ways is 4096.

3 0

3 years ago