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Advocard [28]
3 years ago
7

Find dy/dx for 4 - xy = y^3

Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:

 4-x*y-(y^3)=0


Step by step solution :

Step  1  :

Step  2  :

Pulling out like terms :

2.1     Pull out like factors :


  -xy - y3 + 4  =   -1 • (xy + y3 - 4)


Trying to factor a multi variable polynomial :

2.2    Factoring    xy + y3 - 4


Try to factor this multi-variable trinomial using trial and error


Factorization fails


Equation at the end of step  2  :

 -xy - y3 + 4  = 0

Step  3  :

Solving a Single Variable Equation :

3.1     Solve   -xy-y3+4  = 0


Step-by-step explanation:


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Answer:140ft2

Step-by-step explanation: area= base times height

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                                             Area=140ft2

8 0
2 years ago
What is the rule when multiplying or dividing by a negative number to solve inequalities?
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You flip the inequality.
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3 years ago
Read 2 more answers
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

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2 years ago
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Answer:

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Step-by-step explanation:

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