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RSB [31]
3 years ago
8

Rank the compounds by the ease with which they ionize under sn1 conditions. rank the compounds from easiest to hardest. to rank

items as equivalent, overlap them. resethelp hardesteasiest

Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0
The rate of Formation of Carbocation mainly depends on two factors'

                    1)  Stability of Carbocation:
                                                              The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.

                     2) Ease of detaching of Leaving Group:
                                                                                   The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,

                                            R-I > R-Cl > R-F

                                               B   >  C  >  A

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How many grams of magnesium chloride can be produced if we react 32.50 g Mg with 32.50 g HCl
daser333 [38]
First, you will have to write out and balance the equation, so:

Because we’re looking at a single element reacting with an acid, we know that the reaction must be a single replacement.

Mg + HCl —-> MgCl2 + H2

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Now it needs to be balanced, so you get:

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Now we have molar ratios to do our conversions

So we’ll use stoichiometry to find the theoretical yield for both reactants, and whichever one is the LEAST is the answer.

(32.5g Mg) (1mol/24.3g) (1mol MgCl2/1 mol Mg) (95.3g/1 mol MgCl2) = 127.5g

(32.5g HCl) (1mol/36.5) (1mol MgCl2/2mol HCl) (95.3g/1 mol MgCl2) = 42.4g

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bonufazy [111]

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