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liq [111]
3 years ago
13

Name the form of carbon used for absorbing poisonous gases and purification of noble gases​

Chemistry
1 answer:
Mars2501 [29]3 years ago
7 0
Activated carbon, also called activated charcoal, is a form of carbon processed to have small, low-volume pores that increase the surface area available for adsorption or chemical reactions.
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What is the molarity of 122.5 g of AlCl3 in 1.0 L of solution? (MM = 133 g/mol)
yawa3891 [41]
Answer: Molarity is defined as moles of solute per liter of solution. So, find the moles of solute and divide by the liters of solution.
molar mass AlCl3 = 133g/mole
moles AlCl3 = 127 g x 1 mole/133 g = 0.955 moles
liters of solution = 400 ml x 1 liter/1000 ml = 0.400 liters
Molarity = 0.955 moles/0.400 liters = 2.39 M
Explain: I looked it up on wyzant.com
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I need help with this
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Answer:

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Which set of numbers gives the correct possible values of I for n = 22
Alexandra [31]

Answer:

Hello friends

Explanation:

<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>

<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>

<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>

<h3>Hope it's helpfully. </h3>
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What is the change of state involved in combustion of an alcohol and it’s entropy ?
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3 years ago
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
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