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Jobisdone [24]
3 years ago
12

0.2(6x+1)/3.6 = 0.5x/9 please include work

Mathematics
1 answer:
sergey [27]3 years ago
8 0

0.2(6x+1)/3.6=0.5x/9


We move all terms to the left:


0.2(6x+1)/3.6-(0.5x/9)=0


We add all the numbers together, and all the variables


0.2(6x+1)/3.6-(+0.5x/9)=0


We get rid of parentheses


0.2(6x+1)/3.6-0.5x/9=0


We calculate fractions


There is no solution for this equation

   

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What is the equation for the line that passes through the points (-2,1) and (1,-11)
givi [52]

Answer:

y=4x+7

Step-by-step

(-2,1) and (1,-11)

1)Rule you should use is run over rise aka slope

y²-y^1=

x^2-x^1=

(-11)-1=12

1-(-2)=3

12/3=4

slope =4

2)Rule of point slope intercept

y - y1 = m(x - x1)

y+1=4(x+2)

y+1=4x+8

   -1     -1

y=4x+7

8 0
3 years ago
The initial cost of an office fax machine is $100. After 1 year, its value becomes $80. Which is the correct linear depreciation
Elis [28]

Answer:

y=100-20x

Step-by-step explanation:

Let the x-axis be the time (in years) and the y-axis the value of the fax machine (in dollars).

We know that the initial value of the fax machine is $100; in other words, when the time is zero years, the value is $100, or as an ordered pair (0, 100). We also know that after 1 year the value decreases to $80, so (1, 80).

Now we can find the slope of the line passing through those two points using the slope formula

m=\frac{y_2-y_1}{x_2-x_1}

where

m is the slope

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

Replacing values:

m=\frac{80-100}{1-0}

m=-20

Now, to complete our model we are using the point slope formula

y-y_1=m(x-x_1)

where

m is the slope

(x_1,y_1) are the coordinates of the first point

Replacing values:

y-100=-20(x-0)

y-100=-20x

y=-20x+100

y=100-20x

We can conclude that the correct linear depreciation model is y=100-20x

7 0
3 years ago
For the love of God, please answer this.<br> thanks, W.
Andrew [12]

The equation of the perpendicular line will be y = (4/3)x.

<h3>What is a linear equation?</h3>

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

Then the equation of the perpendicular line will be given as

y = - (1 / m)x + c

The equation of line is y = -3/4 x + 1.

Then the equation of the perpendicular line will be

y = 4/3 x + c

The equation is passing through (9, 12), then we have

12 = 4/3 (9) + c

12 = 12 + c

c = 0

Then the equation of the perpendicular line will be y = (4/3)x.

More about the linear equation link is given below.

brainly.com/question/11897796

#SPJ1

8 0
2 years ago
Step 1 ax2 + bx + c = 0
butalik [34]

Answer:

step three

Step-by-step explanation:

-

s

s

s

d

d

d

sdddde

e

e

7 0
3 years ago
Some one help me i lost with this thing
egoroff_w [7]

Answer:

Im in middle school

Step-by-step explanation: I have no clue how to help u and bc I have no idea how brainy works -_-

4 0
3 years ago
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