Question

Big sleds must hold 3 children and small sleds must hold 2 children.

Answer 1

Answer:

5 big sleds and 1 small sled

Big sled=3 children

5 big sleds=3*5

3*5=15

5 big sleds=15 children

1 small shed=2 children

15+2=17

Answer 2

Since 2 big sleds carry the same number of children as 3 small sleds you could have:

5 big sleds and 1 small = 5x3 + 1x2 = 17

3 big sleds and 4 small = 3x3 + 4x2 = 17

1 big sled and 7 small = 1x3 + 7x2 = 17