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zheka24 [161]
2 years ago
10

3.) A ____ to a theorem is a statement tht follows immediately from the theorem.

Mathematics
1 answer:
Sveta_85 [38]2 years ago
5 0
3.  <span>Corollary
4.  Congruent Polygons
</span>
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In ΔMNO, the measure of ∠O=90°, ON = 35, NM = 37, and MO = 12. What is the value of the tangent of ∠M to the nearest hundredth?
svet-max [94.6K]

Answer:

2.92 Rounded to the 100th

Step-by-step explanation:

4 0
3 years ago
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The volume of the oblique cylinder is 24 ft3.
Marianna [84]

Answer:

A)    C)     E)

Step-by-step explanation:

ON edge

7 0
3 years ago
Please help and show work
mylen [45]
7.B
\sqrt{\pi } = 1.772
\pi = 3.142
2 \times \pi = 6.283
{\pi}^{2} = 9.869

9.A
3/2=1.5

8. F
2times pi =6.283
square root of 50= 7.071
pi squared/2= 3.289

10.H
1/7= .143
which means it can't be f or g.

8 0
3 years ago
Two friends sold many pieces of furniture and made ​$1550 during their garage sale. They had fifteen more​ $10 bills than​ $50 b
Novosadov [1.4K]

Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

3 0
2 years ago
How do I solve 16 = 5x - 9
Darya [45]
16=5x_9

16=_9+5
16 +_5x=_9+5x+_5x

16 + -5x=_9+0
3 0
3 years ago
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